We’ll solve for A. First we will find the possibilities for A by the row and then A by the column.
A by the row: Unique combination
According to A’s column: A+B = 4
The only possible combination for A and B are 3 and 1 (in some order).
Possible values for A by the row:
| By: | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
| Row | NO | NO | NO | NO | NO | NO | NO |
A by the Row: Lowest Possible – 2 Cells
According to A’s row: A+C = 12
If A was 2, then C would have to be 10 and that is not possible. So A is 3 or greater. The LOWEST possible value for A or C is 3.
Possible Values for A by the column are:
| By: | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
| Column | NO | NO |
Solve for A: Combine Row and Column Possibilities
Combine row possibilities (A = 1 or 3) and column possibilities (A >= 3). The only value that would make both of these possible is A=3.
| By: | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
| Row |
NO |
|
NO |
NO |
NO |
NO |
NO |
NO |
|
| Column | NO |
NO |
|
|
|
|
|
|
|
| Both | NO |
NO |
YES |
NO |
NO |
NO |
NO |
NO |
NO |
So A=3.
Solve B,C Complete Sums
Solve B: A+B=4; 3+B=4; B=4-3; B=1
Solve C: A+C=12; 3+C=12; C=12-3; C=9


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